6) A 3.2 cm long line represents a length of 4 meters. Extend this line to measure lengths up to 25 meters and show on it units of meter and 5 meters. Show the length of 17 meters on this line.
Sol) Given data:
RF = 3.2 cm/ 4 m = 3.2/ (4 X 100) (1 m = 100 cm) = 1/125.
Max Length (ML) = 25 m; (no. of parts of scale (n) =5 parts, each is 5 m) Length of scale (LOS) = RF X ML (in cm) = (1/125) x 25 x 100 cm (1 m=100cm) = 20 cm.
The length of the line that is drawn on the drawing sheet is 20 cm.
The sub scale is to be divided into 5 parts.
The length to be shown is 17 m = 15 m (on main scale) + 2 m (on sub scale)
Sol) Given data:
RF = 3.2 cm/ 4 m = 3.2/ (4 X 100) (1 m = 100 cm) = 1/125.
Max Length (ML) = 25 m; (no. of parts of scale (n) =5 parts, each is 5 m) Length of scale (LOS) = RF X ML (in cm) = (1/125) x 25 x 100 cm (1 m=100cm) = 20 cm.
The length of the line that is drawn on the drawing sheet is 20 cm.
The sub scale is to be divided into 5 parts.
The length to be shown is 17 m = 15 m (on main scale) + 2 m (on sub scale)
Very useful sir ,thank you
ReplyDeleteWell explained sir
ReplyDeleteThank you so much sir, very much useful
ReplyDeleteThk u ...keep it up for our bright future 🤗🤗
ReplyDelete